11B - Jumping Jack - CodeForces Solution


math *1600

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Python Code:

import sys
input=sys.stdin.readline
def inp():
    return int(input())
def st():
    return input().rstrip('\n')
def lis():
    return list(map(int,input().split()))
def ma():
    return map(int,input().split())
t=1
while(t):
    t-=1
    n=inp()
    n=abs(n+0)
    cur=1
    mo=0
    x=0
    while(1):
        if((x+cur)<n):
            cur+=1
            mo+=1
            x+=cur-1
        else:
            cur+=1
            mo+=1
            x+=cur-1
            break
    if((x-n)%2):
        x+=cur
        if((x-n)%2==0):
            mo+=1
        else:
            mo+=2
    if(n==0):
        mo=0
    print(mo)
            
    
    
    
    
        

C++ Code:

#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

#define int long long
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> pbds; // find_by_order, order_of_key
#define ld long double
#define vll vector<int>
#define vpl vector<pair<int, int>>
#define pb push_back
#define all(n) n.begin(), n.end()
#define rev(n) reverse(n.begin(), n.end())
#define fr(n) for(int i=0; i<n; i++)
#define frl(k,n) for(int j=k; j<n; j++)
#define cinv(a,n) for(int j=0;j<n;j++) cin>>a[j]
#define yn(x) cout << ((x) ? "YES\n" : "NO\n")
#define endl '\n'
const int M = 1e9+7;

bool poweroftwo(int n) { return !(n & (n - 1)); }
int pow(int a, int b, int m=M) {int ans=1;while (b){if(b&1) ans=(ans*a)%m; a=(a*a)%m; b >>= 1;}return ans;}
// const int N = 4e4;
// bool seive[N]; vector<int> primes;
// void know_all_primes(){for(int i = 2; i < N; ++i){seive[i] = true;}for(int i = 2; i < N; ++i){if (seive[i]) {primes.push_back(i);for(int j = i *i; j < N; j += i){seive[j] = false;}}}}
vector<int> know_all_prime(int num) { vector<int> ans; for(int i=2; i*i<=num; i++) { if(num%i==0) { ans.push_back(i);} while (num % i == 0) { num /= i;}} if (num > 1){ ans.push_back(num); } return ans; }

mt19937 rng((int)std::chrono::steady_clock::now().time_since_epoch().count());

void testCase(){
    int n = 0, m = 0, c = 0, k = -1, sum = 0; string s; bool f = true;
    cin >> k;
    k = abs(k);
    m = 2*k;
    c = sqrt(m);
    n = c*(c+1);
    if(n == m) {
        cout << c << endl; return;
    }
    if(n/2 > k) c--;
    n = c*(c+1)/2;
    sum = k - n;
    if(sum&1 and c&1) cout << c+2 << endl;
    else if(sum%2==0 and c%2==0) cout << c+3 << endl;
    else cout << c+1 << endl;
}   

signed main(){
    ios_base::sync_with_stdio(0); cin.tie(0);
    int test = 1;
    // cin >> test;
    while(test--)  {testCase();}
    return 0;
}


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